12y-1.2y^2=0

Solution for 12y-1.2y^2=0 equation:

12y-1.2y^2=0

a = -1.2; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-1.2)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-1.2}=\frac{-24}{-2.4}
=+10
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-1.2}=\frac{0}{-2.4}
=0
$